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The Silent Auction
Students raise money at their school's silent auction.
June 30, 2008
From the introduction, the six bids came from three girls (Chelsea, Laurie, Rebecca) and three boys (Drew, Micah, Sean), each of whom is in a different class K-5th grade. By clue 1, the Young boy bid twice as much as Micah; while by clue 3, Sean bid twice as much as the 4th grader. Since by the introduction no two bids were for the same amount and since Sean isn't the Young boy (clue 8) and the 4th grader isn't the Young boy (11), four of the six bidders are named between clues 1 and 3. By clue 6, the 3rd grader bid twice as much as the Price girl. Micah isn't the 3rd grader (clue 1), so there is no overlap between clues 1 and 6; while the 4th grader isn't the Price girl (11), so there is no overlap between clues 3 and 6. Therefore, all six bidders for the painting by Mrs. Whyeth are named in clues 1, 3, and 6. Then either the Young boy (1), Sean (3), or the 3rd grader (6) bid $50 (12). If Sean had bid the $50, the 4th grader would have bid $25 (3). The low bid of $10 (12) then would have been made by Micah (1) or the Price girl (6). If Micah had bid $10, the Young boy would have bid $20 (1). The 3rd grader and the Price girl in clue 6 would be the 5th and 6th bidders. By clue 2, Chelsea bid $5 more than the Joyner girl, Chelsea couldn't be the 4th grader or both the Joyner girl and the Young boy would have bid $20. If Chelsea were the Price girl, the Joyner girl would have to be the 4th grader--but the 3rd grader would have bid $60. Chelsea would be the 3rd grader. The Joyner girl would be the 4th grader, so Chelsea would have bid $30 (2) and the Price girl $15 (6). However, there is no way for clue 5 to work given this arrangement. If Sean had bid $50 and the Price girl in clue 6 had bid the low of $10, the 4th grader would have bid $25 (1) and the 3rd grader $20 (6). The Young boy and Micah in clue 1 would be the 5th and 6th bidders. Since Chelsea bid $5 more than the Joyner girl (2), Chelsea would have to be the 4th grader and the Joyner girl the 3rd grader. Again, however, there is no way for clue 5 to work. So, Sean did not bid the high of $50. If the 3rd grader in clue 6 had bid $50 and the Price girl then $25, either Micah (1) or the 4th grader (3) would have bid the low of $10 (12). If Micah had bid $10 and the Young boy then $20 (1), Sean and the 4th grader would be the 5th and 6th bidders. The Joyner girl in clue 2 would have to be the 4th grader. However, Chelsea couldn't be the Price girl or both the Joyner girl and the Young boy would have bid $20; nor could Chelsea be the 3rd grader, or Sean would have bid $90. Trying the second possibility with the 3rd grader making the $50 bid and the Price girl bidding $25 (6), if the 4th grader had bid $10, Sean would have bid $20 (3). Micah and the Young boy would be the 5th and 6th bidders. The Joyner girl in clue 2 would have to be the 4th grader, with Chelsea then having bid $15--impossible given the arrangement. Therefore, the 3rd grader didn't bid $50; the Young boy did, with Micah bidding $25 (1). Either the 4th grader (3) or the Price girl (6) bid $10 (12). If the Price girl had made the low bid, the 3rd grader would have bid $20 (6). Sean and the 4th grader in clue 3 would be the 5th and 6th bidders. If the Joyner girl in clue 2 were the 3rd grader, Chelsea would have bid $25, same as Sean. The Joyner girl would be the 4th grader. Chelsea would have to be the 3rd grader with a $20 bid, the Joyner girl would have bid $15 (2), and Sean would have bid $30 (3). However, clue 5 cannot fit into this arrangement. So, the Price girl didn't make the low bid; in clue 3, the 4th grader bid $10 and Sean bid $20. The 3rd grader and the Price in clue 6 girl are the 5th and 6th bidders. By clue 2, Chelsea didn't bid $10. If Chelsea were the 3rd grader, the Joyner girl would be the 4th grader. However, Chelsea then would have bid $15 (2) and the Price girl $7.50--no (12). Chelsea is the Price girl, and the Joyner girl in clue 2 must be the 4th grader. Chelsea bid $15 (2) and the 3rd grader $30 (6). Laurie must be the 3rd grader (5), and Sean's last name is Baye. The Young boy is Drew and the Joyner girl Rebecca. By clue 9, Chelsea is in 2nd grade. Drew is in kindergarten (4). Micah is the Askew child and Laurie West (10). By clue 7, Micah Askew is a 1st grader and Sean Baye a 5th grader. In sum, the six silent auction bids for Mrs. Whyeth's painting were

  • Drew Young, K, $50
  • Laurie West, 3rd, $30
  • Micah Askew, 1st, $25
  • Sean Baye, 5th, $20
  • Chelsea Price, 2nd, $15
  • Rebecca Joyner, 4th, $10

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