Word Square 14
 Hit the PITCH out of the park with Word Square 14.
 April 28, 2008
From the introduction, each row and each column of the 6x6 Word Square contains the characters PITCH and a space cell in some order, so that no character or space can be repeated in a row or a column. By clue 1, in row 1 H is immediately followed by I. The H can't be in column 1 with the I in column 2, since the column 2 I is the 5th letter down the column (clue 6). The H can't be in column 2 with the I in column 3, since the column 3 I is 2nd or later down the column (9). The H can't be in column 4 with the I in column 5, since the column 4 H is the last letter down that column (10). The H can't be in column 5 with the I in column 6, since the 1st letter down column 6 is T (2). Therefore, in row 1, H is in column 3 and I in column 4. I is in row 2 of column 3 (9). By clue 13, C is the 1st letter down both columns 2 and 5, so that column 2 has C in row 1 with column 5 having C in row 2 with space in row 1, or column 5 has C in row 1 with column 2 having C in row 2 with space in row 1. Trying the first case, by clue 7, the row 4 P would be in column 4 with the row 2 space then in column 6--no (3). So, by clue 13, column 5 has C in row 1 with column 2 having C in row 2 with space in row 1. T is in column 6, row 1 (2) and, by elimination, P is in column 1 of row 1. By clue 5, C is the 1st letter across row 3; since the column 2 C is in row 2, the row 3 C must be in column 1. By clue 6, the column 2 I is in row 6. Then the row 5 I is in column 1 (11). The column 1 H is in row 6 (14). By clue 8, TC are in direct order across row 4--so the column 1 T can't be in row 4 and is in row 2, with the column 1 space in row 4. By clue 10, the column 4 H is in row 5 with the column 4 space in row 6. Since the row 5 space isn't in column 3 (12), the column 3 space is in row 3. Since the row 2 space isn't in column 4 and isn't in column 6 (3), it must be in column 5. By elimination, the row 5 space is in column 6. In row 2, P is in column 4 (7) and H in column 6. In row 3, H isn't the 4th letter across (4); H must be in column 2. By elimination, the row 4 H is in column 5. The column 5 I is in row 3, with the column 6 I in row 4. In row 3, P is in column 6 and T in column 4. The C in column 4 is in row 4 and the C in column 6 in row 6, with the row 4 T then in column 3 (8). Completing row 4 is P in column 2, with T in row 5 completing column 2. Row 6 T is in column 5, with column 5 P then in row 5. C in row 5 is in column 3, with P in column 3 in row 6 finishing the solution. In sum, Word Square 14 is filled as follows:

 1 2 3 4 5 6 1 P H I C T 2 T C I P H 3 C H T I P 4 P T C H I 5 I T C H P 6 H I P T C