From the introduction, the top five salesmen sold a total of 2,000 dozen Tim
Horton's doughnuts, with no two of them selling the same number dozen. By
clue 10, 5th highest salesman sold 200 dozen. Three of the top five are
mentioned in clue 9: Lemieux, who sold 100 dozen more than Peter, who sold
200 dozen more than the defenseman. By clue 5, Eric sold twice as many dozen
as Esposito. Eric isn't Lemieux (clue 1), so either Eric is the defenseman
or Eric is the fourth top salesman to the three listed in clue 9. If Eric
were the defenseman and we let Esposito be the boy who sold the least number,
200 dozen Tim Horton's doughnuts (10), Eric would have sold 400 dozen (5).
Peter's sales total would have been 600 dozen, and the Lemieux boy would have
sold 700 dozen doughnuts (9)a total of 1,900, leaving the fifth winner with
100 dozen in sales and contradicting clue 10. If we let Esposito having sold
more than the 200, the fifth person would have sold even fewer. So, Eric isn't
the defenseman; he is the fourth top salesman to the three in clue 9. In
clue 5, then, either Esposito is Peter, Esposito is the defenseman, or
Esposito is the fifth top salesman to the four already recovered. If Esposito
were Peter and we let the boy who plays defense be the 200 dozen salesman (10),
by clues 5 and 9, Peter Esposito would have sold 400 dozen, Lemieux 500 dozen,
and Eric 800a total of 1,900, leaving the fifth boy with 100 dozen in sales
and contradicting clue 10. If the defenseman had sold more than the
200 dozen, of course, the fifth person would have sold even fewer than 100.
Therefore, Esposito isn't Peter. If Esposito were the defenseman, either
Esposito would have sold 200 dozen doughnuts or Esposito would have been the
4thhighest salesman. If Esposito were the defenseman and sold 200 dozen,
both Eric (5) and Peter (9) would have had sales of 400by the introduction,
no. Trying Esposito as the defenseman and 4thhighest salesman, by clue 10, the
four highest salesmen sold 1,800 dozen doughnuts. Letting Esposito's sales equal
X, by clues 5 and 9, Peter's would have been X + 200, Lemieux's X + 300, and Eric's
2X, so that 5X + 500 would equal 1,800, or X would equal 260. So Esposito
would have sold 260 dozen of Tim Horton's doughnuts, Peter 460, Lemieux 560,
and Eric 520. By clue 2, the boy who plays center sold twice as many dozen
as teammate Howe. There is no way for this clue to work given the arrangement
with Esposito as defenseman and 4thhighest salesman. So, Esposito is the
fifth player to the four already recovered: Lemieux, Peter, the boy who plays
defense, and Eric. Either Esposito or the defenseman sold the low of 200
dozen doughnuts (10, 5, 9). If Esposito had, then Eric would have sold 400
dozen (5), leaving 1,400 in sales for the three in clue 9. Letting the
defenseman's sales be X dozen, Peter's would be X + 200 and Lemieux's
X + 300or 3X + 500 equals 1,400 and X = 300. So, the defenseman would have
sold 300 dozen, Peter 500, and Lemieux 600. The only way clue 2 could fit
into this arrangement would be if Howe were the defenseman and Lemieux the
centerno (6). Therefore, the defenseman sold 200 dozen Tim Horton's
doughnuts, Peter sold 400, and Lemieux sold 500 (9), a total of 1,100 and
leaving 900 between Eric and Esposito (intro). By clue 5, Eric was top
salesman with 600 and Esposito fourth with 300. By clue 2, Howe is the boy
who plays defenseman; and Peter is the center. By clue 3, Tony is Lemieux.
Chad is Esposito and Alex Howe (8). Neither Eric (4) nor Chad (8) plays
right wing, so Tony does. By clue 1, Eric is the team goalie; so Chad is
the left wing. Eric is Orr and Peter Clarke (7). In sum, the top five
Tim Horton's doughnuts salesmen among the Summerset Sticks are
 Eric Orr, goalie, 600
 Tony Lemieux, right wing, 500
 Peter Clarke, center, 400
 Chad Esposito, left wing, 300
 Alex Howe, defenseman, 200


