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Holes-in-One
The Palmer children score aces in a round of Mini-Putt golf.
August 21, 2006
From the introduction, each Palmer child scored his or her hole-in-one on a different hole of the 18-hole miniature golf course. By clue 1, Alexis scored her hole-in-one 6 holes before another child aced the Loop-D-Loop; while by clue 5, the child who played with the orange ball scored a hole-in-one 6 holes before Brendan did. Since Alexis didn't use the orange ball (clue 11) and the child who used the orange ball didn't ace the Loop-D-Loop (clue 9), four different children are named between the two clues. In clue 8, then, where the Palmer child who used the blue golf ball scored a hole-in-one 6 holes before a sibling aced the Parachute, there must be some commonality with clue 1 or clue 5 or six different children would be named among the three clues. Since Brendan didn't use the blue ball (2) and the player who scored a hole-in-one on the parachute didn't use the orange ball (11), clue 8 does not overlap with clue 5. Since Alexis didn't score her ace on the Parachute (11), the player who used the blue golf ball scored a hole-in-one on the Loop-D-Loop. So, we have all five Palmer children named: Alexis scored a hole-in-one 6 holes before her sibling who played with the blue ball aced the Loop-D-Loop and 12 holes before another sibling scored a hole-in-one on the Parachute, while the player who used the orange ball scored a hole-in-one 6 holes before Brendan did. By clue 3, either Alexis or the golfer who used the orange ball aced the 1st hole on the course. If the child who played the orange ball aced the 1st hole, Brendan would have scored a hole-in-one on the 7th hole (5). By clue 10, the child who played with the red golf ball scored a hole-in-one 9 holes before one of the Palmer children aced the Windmill. If Brendan were the one who used the red ball, Alexis would have aced the Windmill, which would be the 16th hole. However, the Loop-D-Loop would then be the 22nd hole (1)--no, since the course is 18 holes. If Alexis were the one who used the red ball, there would be no way for the Windmill to fit 9 holes later. If the child who aced the Parachute had used the red ball, there would again be no way for the Windmill to fit 9 holes later. So, the child who used the orange ball didn't ace the 1st hole; Alexis did. The Loop-D-Loop is then the 7th and the Parachute the 13th hole. Again by clue 10, the child who used the red ball scored a hole-in-one 9 holes before the child who aced the Windmill. The child who used the red ball couldn't have aced the Parachute or the Windmill would be the 22nd hole. Brendan couldn't have used the red ball because Alexis would then have aced the Windmill. So, Alexis used the red ball, and the Windmill is the 10th hole. Brendan didn't ace the Windmill (2), so the child using the orange ball did. Brendan scored a hole-in-one on the 16th hole (5). By clue 3, the 1st hole is the Ski Jump and the 16th is Double Trouble. If in clue 7 Chad had aced the 13th hole (the Parachute), Brendan would have used the yellow ball and Chad then the green--no (4). Chad scored a hole-in-one at the Windmill, and the golfer who aced the Parachute did so with a yellow ball (7). Brendan played with a green ball. Finally, by clue 6, Erica aced the Parachute and David the Loop-D-Loop. In sum, the Palmer scored holes-in-one on the Summerset Mini-Putt course as follows:

  • Alexis, using the red ball, on 1--the Ski Jump
  • David, using the blue ball, on 7--the Loop-D-Loop
  • Chad, using the orange ball, on 10--the Windmill
  • Erica, using the yellow ball, on 13--the Parachute
  • Brendan, using the green ball, on 16--Double Trouble,

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