|From the introduction, Dr. Corwin spent a total of two hours treating the
pets, with no two receiving the same number of minutes with the vet. By
clue 3, Dr. Corwin spent 60 min. total with the 2nd-4th patients and
therefore 60 min. between the 1st and 5th dogs. By clue 4, the longest
amount of time Dr. Corwin spent with any single pet was 45 min. In clue 6,
three of the pets are listed in order of consecutive treatment: the one
with which Dr. Corwin spent 10 min., the dachshund, and Chester--so the
10 min. treatment was the 1st, 2nd, or 3rd. If it had been 1st, by clue 3,
the last treatment would have been for 50 min.--more than the 45 min.
maximum (clue 4). If Dr. Corwin had treated his 3rd patient for the 10 min.,
the dachshund and Chester would then have been the 4th and 5th family dogs
treated (6). If the dachshund were Belle, by clue 5, it would have taken
the vet 25 min. to treat her. However, by clue 3, since the 2nd-4th
treatments took an hour total, the 2nd treatment would also have required
25 min.--a conflict with the intorduction statement that no two treatments
took the same time. By clue 5, Belle's treatment couldn't have taken the
10 min. So, Dr. Corwin would have treated Belle 2nd (5). Dr. Corwin then
couldn't have spent the maximum 45 min. (4) in the 1st treatment or he
would have worked with Belle for 60 min. (5). Dr. Corwin couldn't have
treated Belle for the 45 min. maximum--if he had, the 1st treatment would
have taken 30 min., treatments 2-4 60 min., and the 5th treatment then also
30 min. (3), contradicting the intro. The dachshund treatment's couldn't
have taken 45 min. or Belle's would have lasted 5 min. (3)--impossible (5).
So, Dr. Corwin would have spent 45 min. on the 5th treatment and 15 min. on
the 1st (by clue 3, the 1st and 5th treatments totalled 60 min.). He would
have then spent 30 min. on the golden retriever (7) and on Belle (5), which
by the intro would have to have been the same treatment--no (1). Therefore,
there is no way for Dr. Corwin to have spent the 10 min. on the 3rd treatment.
He spent the 10 mins. with the 2nd dog he treated, treated the dachshund 3rd,
and Chester 4th (6). Belle can't be the 1st or 2nd pet treated (5). If she
were 3rd, then it would have taken Dr. Corwin 25 min. with the her (5).
But, by clue 3, it also would have taken Dr. Corwin 25 min. on the 4th
treatment--by the intro, a conflict. So, Dr. Corwin treated Belle 5th. Belle
isn't the golden retriever (1). The golden retriever also wasn't the 1st
animal treated (7). If the golden retriever had been the 2nd pet treated
and had taken 10 min., then the 1st treatment would have taken 5 min. (7) and
the 5th one 55 min. (3), contradicting clue 4. So, the golden retriever was
treated 4th and is Chester. The treatment on which Dr. Corwin spent the
45 min. wasn't the 1st (7). It can't be the dachshund's treatment, or the
golden retriever's would have taken 5 min. (3), impossible (7, 4). It also
wasn't the golden retriever's treatment, or Belle's treatment would have taken
longer (5). Belle's treatment too the longest, 45 min. Then the golden
retriever's took 30 min. (5), the dachshund's 20 min. (3), and the 1st one
15 min. (7). By clue 2, the 1st family dog Dr. Corwin treated was Muffin,
and the schnauzer was the 2nd. The schnauzer is Fritz and the dachshund
Elmo (2). Dr. Corwin treated the poodle 1st and the Lhasa apso for the 45 min.
(4). Dr. Steve Corwin thus spent the following times to treat the five family
pets in order
- Muffin, poodle, 15 min.
- Fritz, schnauzer, 10 min.
- Elmo, dachshund, 20 min.
- Chester, golden retriever, 30 min.
- Belle, Lhasa apso, 45 min.